Board Thread:Questions and answers/@comment-26431461-20160616150111/@comment-27035444-20160616160357

(puts on nerd glasses) Let's see. Using algebraic notation and judging by Newton's second law, if one were to measure how many feet per second an object travels, they would have to do the following: First, get a measurement on the object. Second, find the vector calculus. Then, this said person must find the square route of pi (delicous). Next step would be multiplying the product of the square route of pi and the vector calculus of the object. Using that number, divide it by the volume of the object in centimeters. Next, find the range of the said object in centimeters or millimeters, prefereably the latter. Once more find the vector calculus and multiply the number of centimeters/millimters by this formula (bear in mind you must multiply the measurement according to whether or not you found the distance in millimeters or centimeters. one thousand for millimeters, or one hundred for centimeters): x=''vector caculus subtracted by the square route of pi. ''once completing that, you should have your feet per second within the hundredth of a foot per second.

Easy enough, right?